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<p>to Q2 base that keeps Q2 firmly off. C1 begins discharging (reverse charging) via the high-value base <a href="page.php?w=resistor">resistor</a> R2, so that the voltage of its right-hand plate (and at the base of Q2) is rising from below ground (-V) toward +V. As Q2 base-emitter junction is reverse-biased, it does not conduct, so all the current from R2 goes into C1. Simultaneously, C2 that is fully discharged and even slightly charged to 0.6 V (in the previous State 2) quickly charges via the low-value collector resistor R4 and Q1 forward-biased</p><p>
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