1.Previous
3.Next

the numbers 1, 2, 4, 8, 16, 31, 62, 124 and 248 add up to 496 and further these are all the numbers that divide 496. For suppose that divides 496 and it is not amongst these numbers. Assume is equal to , or 31 is to as is to 16. Now cannot divide 16 or it would be amongst the numbers 1, 2, 4, 8 or 16.Therefore, 31 cannot divide . And since 31 does not divide and measures 496, the fundamental theorem of arithmetic implies that must divide 16 and

1.Previous
3.Next