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<p>cover of ) <br/>
:Let  be a topological space, and  be a subbase of  If  is compact, then every cover of  by elements from  has a finite subcover.</p>

<p>Although this proof makes use of <a href="page.php?w=Zorn%27s_Lemma">Zorn's Lemma</a>, the proof does not need the full strength of choice. Instead, it relies on the intermediate <a href="page.php?w=Ultrafilter_principle">Ultrafilter principle</a>.</p>

<p>Using this theorem with the subbase for  above, one can give a very easy proof that bounded closed intervals in  are compact.  More generally,</p><p>
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