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<p>every projection operator  of rank  defines a subspace  as its image. Since the rank of an orthogonal projection operator equals its <a href="page.php?w=trace_of_a_matrix">trace</a>, we can identify the Grassmann manifold  with the set of rank  orthogonal projection operators :  <br/>
::</p>

<p>In particular, taking  or  gives completely explicit equations for embedding the Grassmannians ,  in the space of real or complex  matrices , , respectively.</p>

<p>Since this defines the Grassmannian as a closed subset of the sphere  the Grassmannian</p><p>
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