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<p>directed graphs, terminals, and partitioning the vertices into more than two sets.</p>

<p>The weighted min-cut problem allowing both positive and negative weights can be trivially transformed into a weighted <a href="page.php?w=maximum_cut">maximum cut</a> problem by flipping the sign in all weights.</p>

<p>__TOC__</p>

<p><big>Without terminal nodes</big></p>
<p>The input is a graph G = (V, E). The required output is a partition V = S + T (a partition of the vertices into two disjoint subsets S and T). Any such partition has a cost, and the goal is</p><p>
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