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<p>{a, b} = c and a = c implies that c is an element of c, contradicting regularity.<br/>
:So we have a = c and {a, b} = {c, d}, and so: {b} = {a, b} \ {a} = {c, d} \ {c} = {d}, so b = d.</p>

<p><big>Quine-Rosser definition</big></p>
<p><a href="page.php?w=J._Barkley_Rosser">Rosser</a> (1953) employed a definition of the ordered pair due to <a href="page.php?w=Willard_van_Orman_Quine">Quine</a> which requires a prior definition of the <a href="page.php?w=natural_number">natural number</a>s. Let  be the set of natural numbers and define first</p>

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