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<p>As an example, the field of <a href="page.php?w=real_number">real number</a>s is not algebraically closed, because the polynomial equation  has no solution in real numbers, even though all its coefficients (1 and 0) are real.  The same argument proves that no subfield of the real field is algebraically closed; in particular, the field of <a href="page.php?w=rational_number">rational number</a>s is not algebraically closed. By contrast, the <a href="page.php?w=fundamental_theorem_of_algebra">fundamental theorem of algebra</a> states that the field</p><p>
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