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<p>finding a solution, backtracking concludes that no solution extending  exists. The algorithm then "goes up" to , changing 's value if possible, backtracking again otherwise.</p>

<p>The partial assignment is not always necessary in full to prove that no value of  leads to a solution. In particular, a prefix of the partial assignment may have the same property, that is, there exists an index  such that  cannot be extended to form a solution with whatever value for . If the algorithm can prove this fact, it can directly consider a different value</p><p>
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