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<p>The halting problem is easy to solve, however, if we allow that the Turing machine that decides it may run forever when given input which is a representation of a Turing machine that does not itself halt.  The halting language is therefore recursively enumerable.  It is possible to construct languages which are not even recursively enumerable, however.</p>

<p>A simple example of such a language is the complement of the halting language; that is the language consisting of all Turing machines paired with input strings where the Turing machines</p><p>
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