Me(Et)C=NNH₂ + H₂OThe hydrazone then condenses with a second equivalent of ketone to give the ketazine:
:Me(Et)C=O + Me(Et)C=NNH₂ -> Me(Et)C=NN=C(Et)Me + H₂O

Typical process conditions are 50 °C and atmospheric pressure, with a feed mix of H₂O₂:ketone:NH₃ in a molar ratio of about 1:2:4. Methyl ethyl ketone is advantageous to acetone because the resulting ketazine is immiscible in