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<p>are provable.  <a href="page.php?w=omega-consistent">&omega;-consistency</a> is a stronger property than consistency.  Suppose that  is a formula with one free variable .  In order to be &omega;-consistent,  the theory cannot prove both  while also proving  for each natural number .</p>

<p>The theory is assumed to be effective, which means that the set of axioms must be <a href="page.php?w=recursively_enumerable">recursively enumerable</a>.  This means that it is theoretically possible to write a finite-length computer program that, if allowed</p><p>
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