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<p>In other words, there are elements k,&nbsp;x<sub>1</sub>,&nbsp;x<sub>2</sub>,&nbsp;...,&nbsp;x<sub>n</sub> of the field F such that p(x)&nbsp;=&nbsp;k(x&nbsp;&minus;&nbsp;x<sub>1</sub>)(x&nbsp;&minus;&nbsp;x<sub>2</sub>)&nbsp;···&nbsp;(x&nbsp;&minus;&nbsp;x<sub>n</sub>).</p>

<p>If F has this property, then clearly every non-constant polynomial in F[x] has some root in F; in other words, F is algebraically closed. On the other hand, that the property stated here holds for F if F is algebraically closed follows from the previous property together</p><p>
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